Question

Cate grame de KOH se contin in 400 ml de solutie cu pH-ul 12

Answer 1

pH+pOH=14---> pOH=2
pOH=- lg[OH⁻].----------> [OH⁻]= 10⁻² mol/l
pentru ca KOH este o baza tare [OH⁻]=[KOH]=0,01mol/l

1000ml........0,01molKOH
400ml...........x=0,004molKOH

M,KOH= 56g/mol
m=n x M=> m= 0,004molx56g/mol=......................calculeaza.