Question

Cate grame de oxigen se pot obtine prin descompunerea a 2.45 g cloratului de potasiu.

Answer 1

2×83,89g              3×32
2KClO3⇒2KCl+3O2
2,45                      x
MKClO3=AK+ACl+3×AO=39+35,5+3×16=83.89g
MO2=2×AO=2×16=32g
x=2,45×3×32\2×83,89=calculeaza