Question

Cate grame se gasesc in 4 moli do azotat de potasiu, 7 moli de dioxid de carbon si 2,5 moli de oxid de calciu. Dau coroana. Imi trebuie pana maine

Answer 1

M KNO3= 39+14+48=101 g/mol
1 mol KNO3...101 g
4 moli KNO3...x g
x=4*101=404 g KNO3
M CO2= 12+32=44 g/mol
1 mol CO2...44 g
7 moli CO2...y g
y=7*44=308 g CO2
M CaO= 40+16=56
1 mol CaO...56 g
2,5 moli CaO...z g
z=2,5*56= 140 g CaO
In total avem x+y+z=404+308+140=852 g