Question

Cate grame se gasesc in:​

Answer 1

a.

acid azotic = HNO3

Miu = 63 g/mol

niu = masa/miu => m = niuxmiu = 63x6 = 378 g HNO3

b.

3,5 kmoli = 3500 moli de MgO

Miu = 40 g/mol

m = miuxniu = 40x3500 = 140000 g = 140 kg MgO

c.

200 mmoli CO2 = 0,2 moli CO2

Miu = 44 g/mol

=> m = niuxmiu = 0,2x44 = 8,8 g CO2

d.

AlBr3

Miu = 267 g/mol

m = niuxmiu = 2x267 = 534 g AlBr3

e.

Cu(OH)2

Miu = 98 g/mol

m = niuxmiu = 1x98 = 98 g

Answer 2

S se foloseste relatia :

n = m : M    in care n=nr. moli ; m=masa subst. ( g )  ; M=masa molara  

                                                                                               ( g/moli  )

a.

m=n . M

m=6moli . 63g/moli=378 g HNO3

b.

m=3500moli . 40g/moli=140000 g=140 kg

c.

200mmoli=0,2 moli CO2

m=0,2moli .44g/moli=8,8 g CO2

d.

m=2moli .267g/moli=534 g AlBr3    

e.

m=1mol. 98g/moli=  98 g Cu(OH)2      

MHNO3=1+14+3.16=63-----> 63g/moli

MMgO=24+16=40---->40g/moli

MCO2=12+2.16=44---->44g/moli

MAlBr3=27+3.80=267------> 267g/moli

MCu(OH)2 = 64 +2.16 +2   =98-----> 98g/moli