Cate molecule de clor se gasesc in:
71 kg Cl2=
2 kmoli de Cl2=
20dm3 de Cl2 aflat la 127°C si 6 atm=
Răspunsuri la întrebare
MCl2=2 . 35,5 = 71--------> 71g/moli
71kg=71000g clor----> n=m:M ; n=71000g : 71g/moli
n=1000 moli clor
1mol clor----------6,023 .10²³ molecule
1000moli ----------------x
x=1000 . 6,023.10²³ =6023 .10²³ molecule clor
2kmoli clor=2000 moli
1mol clor---------------6,023.10²³molecule
2000moli-------------------y
y=2000 . 6,023.10²³molecule clor=
VCl2=20dm³=20litri
t=127 °C
p=6atm.
p V = n .R T
- se afla nr. de moli =n
n=pV : RT
n= 6atm .20 litri : 0,082 l.atm /mol K . ( 127 +273 ); [ simplifici unit.de
=120 : 0,082 . 400 masura]
= 3,66moli clor
1mol clor---------------6,023.10²³ molecule
3,66moli-------------------------z
z=3,66. 6,023.10²³molecule =