Question

cate nr.naturale de forma AB barat,dau restul 4 la împărțirea cu 6?Va rog!


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Answer 1

Abad:ab= c+5
-----------------------
a=?;b=?;d=?;c=?

b<5
d> sau = 5

valorile lui "a" pot fi:....1,2,3,4,5,6,7,8,9
valorile lui "b" pot fi:....0,1;2;3;4...
valorile lui "d" pot fi.....5;7;6;8;9....

c=(abab:2):5............prima valoare abab=>1010...avem deci 2ab...si rest 5
c=(1010:2):5
c=505:5
c=101

abad:ab=101*ab+5

d=b+5

luam primul nr.1010+5=>1015...=>...d=0+5 ...=> abad=1015

abad:ab=   c*ab +5
1015:10=101*10+5=>..101*10+5=1010+5=1015 (a=1;b=0;d=5;c=101;r=5)
1217:12=101*12+5=>..101*12+5=1212+5=1217 (a=1;b=2;d=7;c=101;r=5)
1318:13=101*13+5=>..101*13+5=1313+5=1318 (a=1;b=3;d=8;c=101;r=5)
1419:14=101*14+5=> .101*14+5=1414+5=1419 (a=1;b=4;d=9;c=101;r=5)

2025:25=101 rest 5
2126:21=101 rest 5
2328:23=101 rest 5
2429:24=101 rest 5

abad ab =101 rest 5
3035:30=.101 rest 5
3136:31=.101 rest 5
3237:32=.101 rest 5

4045:40=101 rest 5
4146:41=101 rest 5
4247:42=101 rest 5
4348:43=101 rest 5

5156:51= 101 rest 5
5257:52 =101 rest 5
5358:53 =101 rest 5
5459:54= 101 rest 5

6065:60=101 rest 5
6267:62=101 rest 5
6368:63=101 rest 5
6469:64=101 rest 5

7075:70=101 rest 5
7176:71=101 rest 5
7378:73=101 rest 5
7479:47=101 rest 5

8085:80=101 rest 5
8186:81=101 rest 5
8287:82=101 rest 5
8489:84=101 rest 5

9095:90=101 rest 5...=>101*90+5=9090+5=> 9095
9196:91=101 rest 5
9297:92=101 rest 5
93:98:93=101 rest 5..=>101*93+5=9393+5=9398

-----------------------------------------------------------------------------------
ab......a...... d.......ab........c.........r.......=>abcd= c rest 5
10      1.......5       10      101      5      =>1015=101  r  5...(1010+5)
12      1       7       12      101      5      =>1217=101  r  5
13      1       8.......13      101      5
14      1       9       14      101      5


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