Question

cate nr. naturale de forma abc,verifica relatia abc-cba=594

Answer 1

$701-107=594$

Answer 2

100a+10b+c-100c-10b-a=594
99a-99c=594
99x(a-c)=594
a-c=594:99
a-c=6⇒a=6+c
Deci ,,a,, trebuie sa fie mai mare decat 6.
a=7⇒c=1 iar b =0,1,2,3,4,5,6,7,8,9
a=8⇒c=2  
a=9⇒c=3
Deci numerele sunt:701,711,721,731,741,751,761,771,781,791,802,812,822,832,842,852,862,872,882,892,903,913,923,933,943,953,963,973,983,993=30 de numere