Question

cate numere are sirul 2,5,8,11,...,299.

Answer 1

   
[tex]\displaystyle n = \frac{299-2}{3}+1 = \frac{297}{3}+1 = 99+1= \boxed{100~de~termeni}[/tex]

Answer 2

$2=3*0+2\\5=3*1+2\\8=3*2+2\\11=3*3+2\\......\\......\\......\\299=3*99+2\\Nr.terminilor:100$