Question

Cate numere naturale de 5 cifre dau restul 12 la impartirea cu 1994 ?

Answer 1

abcde:1994...rest 12
nr cautate sunt
10000$\leq$M1994+12$\leq$99999
(10000-12):1994≈5
si (99999-12):1994≈50
avem (50-5)+1=46

Answer 2

 [tex] \overline{abcde}\;:\;1994\,=\, c\,(rest\;12\;\Leftrightarrow\;10000\leM_{1994}+12\le99999\\ 10 000:1994\approx5\;si\\ 99 999:1994\approx50\\ \overline{abcde}-12=\\ =\{6*1994=11964;7*1994=13958\;...\;50*1994=99700\}\\ Numarul \,acestor], numere\, este:\;(50-6)+1=\fbox{45}[/tex]