Question

Cate numere naturale mai mici decat 600,împărtite la 35dau restul 12

Answer 1

$D=deimpartitul\\I=impartitorul\\R=restul\\600/35=17R5\to R5\ \textless \ R12\\C\in N\\D=I*C+R\\ Dminim=35*0+12=12\\Dmaxim=35*16+12=572\\D\in \left \{35*0+12;35*1+12;35*2+12;35*3+12;....;35*16+12} \right.\}\\ 0 \to 16=16+1=17nr. \\ Dare:17valori \\ Raspuns:17nr. \\ Sfarsit!$