Question

Cati atomi contine un inel de argint care cantareste 1,08 g?

Answer 1

  1 mol Ag .......... 108 g Ag ............6,022 x 10^23 atomi
                              1,08 g Ag ..................x

x = $\frac{1.08 * 6,022 * 10^{23} }{108}$ 
=> [tex]x = 6,022 * 10^{25} [/tex] atomi