Question

cati atomi cuprind 32 g de sulf, dar 4 g de heliu?

Answer 1

se calculeaza numarul de moli cu relatia niu=m./M .apoi, N= niuxNA, unde N,A este numarul lui Avogadro

M,S= 32g/mol---> niu= 32/32 mol=1mol

N,atomi= 1x6.023x10²³atomi= 6,023x10²³ atomiS

SAU

1mol...........32g

x..................32g

x=1mol

1mol  contine  N,Aatomi

1mol..................N= N,A=6,023x10²³atomi

M,He=4g/mol

niu= m/M= 4/4 mol=1mol

N=niuxN,A= 6,023X10²³atomi