Question

Câti atomi există in:
a) 20 moli S
b)0,02 kmoli Au
c) 2 Kg Ag
d) 560 mg Fe
Vă rog!!!!! E urgent!!!​

Answer 1

Explicație:

1 mol de element conține 6,022 × 10²³ atomi.

a)

1 mol S..........6,022 × 10²³ atomi S

20 mol S..........x atomi S

x = 20 × 6,022 × 10²³ = 1,2044 × 10²⁵ atomi S

b) 0,02 kmol = 20 mol

1 mol Au..........6,022 × 10²³ atomi Au

20 mol Au..........y atomi Au

y = 20 × 6,022 × 10²³ = 1,2044 × 10²⁵ atomi Au

c) A(Ag) = 108 g/mol

2 kg = 2000g

1 mol Ag..........108g Ag

z mol Ag..........2000g Ag

z = 2000 : 108 = 18,51 mol Ag

1 mol Ag..........6,022 × 10²³ atomi Ag

18,51 mol Ag..........w atomi Ag

w = 18,51 × 6,022 × 10²³ ≈ 1,1146 × 10²⁵ atomi Ag

d) A(Fe) = 56 mg/mmol

1 mmol Fe..........56 mg Fe

a mmol Fe..........560 mg Fe

a = 10 mmol

1 mmol Fe..........6,022 × 10²⁰ atomi Fe

10 mmol Fe.......... b atomi Fe

b = 6,022 × 10²¹ atomi Fe

-Mihai