Question

cati atomi se gasesc in 64 g de aluminiu

Answer 1

μAl=27 g/mol 

1 mol ....... 6,023 *10²³ atomi
=> 27 g Al ....... 6,023*10²³ atomi
     64 g Al............ x atomi
=> x=14,27 * 10²³

Answer 2

nr de moli (n) = m/A
n= 64/27
n= 2,37 moli Al

1 mol de Al .............6,022*10^23 atomi (nr lui avogadro)
2,37 moli de Al .............. x atomi

x = 6,022*10^23 *2,37
x = 14,27214 *10^23 atomi