Question

Cati atomi sunt cuprinsi in:27gAl;;0,5 molide Li​

Answer 1

Răspuns:

MAl =27g/mol

1 mol Al..........27g........6,023×10²³atomi

27g.........x atomi

x=27×6,023×10²³ atomi/27= calculează

MLi=7g/mol

m=n××M=0,5×7=3,5g/mol

1mol Li........7g...........6,023×10²³atomi

3,5g..........y atomi

y= 3,5×6,023×10²³atomi /7=calculează