Question

Câți divizor naturali au numerele a) 434 b) 162 c) 147 d) 500 e) 775 ​

Answer 1

a) 434 = 2•217 = 2¹•7¹•31¹

- are (1+1)•(1+1)•(1+1) = 8 divizori naturali.

b) 162 = 2•81 = 2¹•3⁴

- are (1+1)•(4+1) = 10 divizori naturali.

c) 147 = 7•21 = 7•3•7 = 3¹•7²

- are (1+1)•(2+1) = 6 divizori naturali.

d) 500 = 5•10² = 5•(2•5)² = 2²•5³

- are (2+1)•(3+1) = 12 divizori naturali.

e) 775 = 5•155 = 5•5•31 = 5²•31¹

- are (2+1)•(1+1) = 6 divizori naturali.