Question

Cati electroni de valenta se gasesc in:
a) 1mol Ag
b)1,4 g Li
c)0,3Kilomoli Al

Answer 1

a) 1atom..................1e⁻ de valenta Ag
6.023*10²³................x
x=6.023*10²³*1/1
x=6.023*10²³ e⁻ de valenta Ag

b) 1mol.......................7g Li
y moli..........................1.4g Li
y=1.4*1/7
y=0.2moli Li

1mol................................6.023*10²³ atomi Li
0.2moli.............................z
z=0.2*6.023*10²³/1
z=1.2046 atomi Li

1atom.......................1e⁻ de valenta Li
1.2046 atomi...............w
w=1.2046*1/1
w=1.2046 e⁻ de valenta Li

c) 0.3kmoli=300moli
1mol..............................6.023*10²³ atomi Al
300moli...........................a
a=300*6.023*10²³/1
a=1806.9 atomi Al

1atom...........................3e⁻ de valenta
1806.9atomi...................b
b=1806.9*3/1
b=5420.7 e⁻ de valenta