Question

Cati moli de 2-butena se pot oxida cu 0,4 moli de KMnO4/H2O?

Answer 1

CH3-CH=CH-CH3 + [O] + H2O ⇒ CH3-CH(OH)-CH(OH)-CH3
2KMnO4+H2O ⇒ 2KOH + 2MnO2 + 3[O]
n butena/nKMnO4 = 3/2    n butena = 3·0,4/2 = 0,6 moli