Question

cati moli de atomi si cati atomi de aluminiu se gasesc in 270 g de aluminiu

Answer 1

n=m/A=270 g/27=10 moli
1mol.............6,022*10(23)
10moli,............x=60,22*10(23)

Answer 2

n=m/M
$n = \frac{270}{ 27} = 10 \: moli \: aluminiu$

1 mol Al............NA atomi Al
10moli..................x

$x = \frac{10 \times 6.022 \times {10}^{23} }{1} \\ x= 60.22 \times {10}^{23} atomi \: de \: aluminiu$