Question

cati moli de zinc se obtin dintr-o tona sulfura de zinc impura de puritate 60% la un randament de 80%? Ma puteți ajuta va rog repede

Answer 1

1000 kg (1 tona) .................. 100%

m.p kg ................................ 60%

= 600 kg ZnS pura

M.ZnS = 65+32 = 97 g/mol ; M.Zn = 65 g/mol

600 kg        m kg

ZnS + H2 --> Zn + H2S

97                  65

=> m = 600x65/97 = 402,06 Kg Zn obtinut teoretic la 100%... dar la 80%..?

100% .......................... Ct. = 402,06 kg

80% ............................. Cp. = 321,65 Kg Zn

=> n. moli = m/M = 321,65/65 = 4,95 kmoli = 4950 moli Zn