Question

Cati moli reprezinta 180 g hidroxid de fier (valenta 3 ) ?
Ajutor! Va rog

Answer 1

MFe(OH)3=56+48+3=108 g

$n = \frac{ms}{masa \: mol}$

mFe(OH)3=180g

$n = \frac{180}{108} = 1.6 \: moli$

Sper ca asa trebuia calculat ;)