Câți moli reprezintă :
a) 0,8 kg carbonat de Ca
b)126kg acid azotic
c)1960g acid sulfuric
d)500 kmoli sulfat Cu
Răspunsuri la întrebare
a. 0,8 kg CaCO3 Se calculeaza masa moleculara
? moli MCaCO3= 40 +12 +3.16=100----->1mol=100g
100g CaCO3-------------1 mol CaCO3
8OO g----------------------x
x=800:100=8 moli CaCO3
0,8 Kg=800 g
b. 126 kg HNO3 M=1 +14 +3.16=63------>1mol=63g
? moli 126kg=126000g
63g-------------1mol HNO3
126000g --------x
x=126000:63=2000 moli HNO3
c. 1960 g H2SO4 M =2 +32 +4.16=98------>1mol=98g
98g H2S04-------------1mol H2S04
1960 g ----------------------x
x=1960: 98=20 moli H2SO4
d. 500 kmoli CuSO4 1Kmol=1000moli
?moli 500 kmoli=500000 moli