Question

Cati moli si ce numar de molecule de hidrogen H2 se obtin prin reactia dintre calciu si 400g solutie de acid clorhidric HCl de kconcentratie 20%? Ajutor. si calculele va rog mult.

Answer 1

Ca + HCl = CaCl₂ + H₂

Md= Ms*c/100
Md= 400*20/100
Md=80 g HCl.

M H₂= 2 ( 1 mol H₂= 2 g)
M HCl= 36.5 (1 mol HCl= 36.5 g)

36,5/80 = 2/x
x= 80*2/36.5
x≈4.38 g H₂

1 mol H₂.......2 g
x moli H₂.......4.38 g

1/x = 2/ 4.38
x= 4.38/2
x= 2.19 moli H₂