Question

Cati termeni are suma 4+6+8...202?

Answer 1

$\displaystyle 4+6+8+10+...+202 \\ \\ 202=4+(n-1) \times 2 \\ \\ 202=4+2n-2 \\ \\ 2n=202-4+2 \\ \\ 2n=200 \\ \\ n= \frac{200}{2} \\ \\ n=100~termeni$