Matematică, întrebare adresată de crucerescoalexandru7, 8 ani în urmă

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Răspuns de martaspinu18
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a)

4 \frac{1}{2}  \div  \frac{2}{3}  =  \frac{4 \times 2 + 1}{2}  \div  \frac{2}{3}  = \\   \frac{9}{2}  \div  \frac{2}{3}  =    \frac{9}{2}  \times  \frac{3}{2}  =  \frac{9 \times 3}{2 \times 2}  =  \frac{27}{4}

b)

 \frac{7}{12}  \div 3 \frac{1}{16}  =  \frac{7}{12}  \div  \frac{3 \times 16 + 1}{16}  =  \\  \frac{7}{12}  \div  \frac{49}{16}  =  \frac{7}{12}  \times  \frac{16}{49}   (simplifici) =  \\ \frac{1}{3}  \times  \frac{4}{7} =   \frac{1 \times 4}{3 \times 7}   =  \frac{4}{21}

c)

5 \div 1 \frac{1}{4}  = 5 \div  \frac{1 \times 4 + 1}{4}  =  \\ 5 \div  \frac{5}{4} = 5  \times  \frac{4}{5}   = 4

d)

2 \frac{2}{3}  \div 2 \frac{1}{3}  =  \frac{2 \times 3 + 2}{3}  \div  \frac{2 \times 3 + 1}{3}  =  \\  \frac{8}{3}  \div  \frac{7}{3}  =  \frac{8}{3}  \times  \frac{3}{7}  =  \frac{8}{7}

e)

4 \frac{1}{2}  \div 3 \frac{1}{2}  =  \frac{4 \times 2 + 1}{2}  \div  \frac{3 \times 2 + 1}{2}  = \\   \frac{9}{2}  \div  \frac{7}{2}  =  \frac{9}{2}  \times  \frac{2}{7}  =  \frac{9}{7}

f)

5 \frac{1}{6}  \div 6 \frac{8}{9}  =  \frac{5 \times 6 + 1}{6}  \div  \frac{6 \times 9 + 8}{6}  =  \\  \frac{31}{6}  \div  \frac{62}{6}  =  \frac{31}{6}  \times  \frac{6}{62}  =   \frac{31}{62}  =  \frac{1}{2}

g)

16 \div 9 \frac{3}{5}  = 16 \div  \frac{9 \times 5 + 3}{5}  =  \\ 16 \div  \frac{48}{5}  = 16 \times  \frac{5}{48}  =  \frac{5}{3}

h)

3 \frac{3}{4}  \div 1 \frac{1}{4}  =  \frac{3 \times 4 + 3}{4}  \div  \frac{1 \times 4  + 1}{4}  =  \\  \frac{15}{4}  \div  \frac{5}{4}  =  \frac{15}{4}  \times  \frac{4}{5}  =  \frac{15}{5}  = 3

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