Question

caut raspunsul la intrebarea camelieide aflat numerele x si y fiind invers proportionale cu numerele 2 si 3 si ca x patrat +y patrat =252

Answer 1

x^2 +y^2 =252

x si y direct proportionale cu 2 si 3, rezulta xy=2*3=6

Avem:

x^2 +y^2 =252
xy=6

x^2 +y^2 =(x+y)^2 -2xy=252

(x+y)^2 -2*6=252

(x+y)^2=252+12=264

(x+y)^2=264

x+y=2V66, "V"=radical

Avem x+y=2V66 si xy=6

Putem creea ecuatia: t^2 -2V66 *x+6=0

t1 si t2 se afla rezolvand ecuatia.

t1;2=(-2V66 +/-V240)/2=(-2V66 +/-4V15)/2=-V66 +/-2V15

x=-V66 +2V15 si y=-V66 -2V15

Sau:

x=-V66 -2V15 si y=-V66 +2V15

Answer 2

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