Question

Caută rezultate pentru sintagma "12+a+14=4a-4 si [(b+3)×3+3]+3=102 sa se calculeze a+b"

Answer 1

12+a+14=4a-4
12+14+4=4a-a
30=3a
a=10

[(b+3)×3+3]+3=102
3b+9+3=102-3
3b=99-12
3b=87
b=29

a+b=10+29=39

Answer 2

12+a+14=4a-4
26+a=4a-4
26+4=4a-a
30=3a
a=30:10
a=10

[(b+3)*3+3]+3=102
[3b+9+3]+3=102
3b+12=102-3
3b+12=99
3b=99-12
3b=87
b=87:3
b=29

Daca a=10 si b=29 atunci putem afla a+b!
===>>>a+b=10+29
===>>>a+b=39