Question

Ce cantitate de aluminiu se gaseste in 100 g de alumina cu 10% impuritati?
Al2O3

Answer 1

p = 100-10 = 90%

p = m pur/m impur×100 => m pur = p×mimp/100 = 90×100/100 = 90g Al2O3

MAl2O3 = 2AAl + 3AO = 2×27+3×16 = 102g/mol

102g Al2O3.....................2×27g Al
90g Al2O3............................xg Al

x = 54×90/102 = 47,647g Al

Good luck !