Question

ce cantitate de apa participa la reactia cu 6 moli de oxid de calciu​

Answer 1

n=m/M

M CaO=40+16=56 g/mol

m=nxM=6×56=336 g

M H2O=2+16=18 g/mol

336.......x

CaO+H2O-->Ca(OH)2

56.........18

x=(18x336)/56

=> x=108 g H2O