Question

Ce cantitate de azot se afla intr-un recipient cu volumu de 10 L,daca cazu are temperatura de 47 Grade C si presiunea de 2 atm.

Answer 1

pV=nRT
p = 2 atm
V = 10 L
R= 0.082 L * atm/ mol *K
T= t + 273.15 K = 47 +273.15=320.15 K

n= pV/RT
n= 2 x 10 / 0.082 x 320.15 = 0.76 mol
m N2 = n x M => m N2 = 0.76 mol x 28 g/mol = 21.33 g N2