Question

Ce cantitate de clorura de potasiu se obtine prin descompunerea a 2,45 g clorat de potasiu?

Answer 1

2 KClO3 = 2 KCl + 3 O2
M KClO3 = 39+35,5+3*16 = 122,5 g/mol
M KCl = 39+35,5 = 74,5 g/mol
2*122,5 g KClO3...........2*74,5 g KCl
2,45 g KClO3.........................x
x = 1,49 g KCl
n = m/M = 1,49/74,5 = 0,02 moli KCl