Question

Ce cantitate de dioxid de sulf(in grame,mol si litri) reazulta din arderea a 60 de grame sulf?

Answer 1

S + O₂ = SO₂

M S = 32 g/mol
M SO₂ = 32+16*2 = 32+32 = 64 g/mol

32/60 = 64/x
x= 60*64/32
x= 3840/32
x= 120 g SO₂

1 mol SO₂.... 64 g
x moli SO₂..... 120 g

1/x = 64/120
x= 120/64
x= 1,875 moli SO₂

1 mol SO₂ = 22,4 l
1,875 moli SO₂ = x l
1/1,875 = 22,4/x
x= 1,875* 22,4
x= 42 l SO₂