Question

Ce cantitate de fier 80%. Reactioneaza cu 400g solutie acid sulfuric c=49%

Answer 1

calculez masa si moli H2SO4 din solutie
c=mdx100/ms
49/100= md/400----. >md= 4x49g
n(niu)= m/M
n= 4x49g/98g/mol= 2molH2SO4-

deduc moli si masa de Fe pur din ecuatia:
1mol      1mol
Fe + H2SO4----> FeSO4 + H2
x..........2mol
x= 2mol Fepur
m= 2molx56g/mol= 112g

calculez masa de Fe de puritate 80%
p= m,px100/m,impur
80/100= 112/m,impur..............................calculeaza !!!!!