Question

Ce cantitate de NaOH poate fi neutralizata cu 146g solutie HCL cuc=10%?.Ce produsi rezulta si in ce cantitate

Answer 1

Răspuns:

Explicație:

ms HCl =146g

c=10%

mNaOH

m  produsi de reactie

-se afla  md  HCl

md=c.ms:100

md=10 .146 :100=14,6 g HCl

    xg        14,6g     yg          zg

 NaOH + HCl   =  NaCl +H2O

40g         36,5g    58,5g    18g

x=40.14,6 : 36,5=16 g NaOH

y=14,6 .58,5 :36,5=23,4 g NaCl

z=14,6 .18 : 36,5=7,2 g H2O

MHCl=1+35,5=36,5------>36,5g/moli

MNaOH=23+16+1=40------>40g/moli

MNaCl=23+35,5=58,5------->58,5g/moli

MH20=2+16=18-------> 18g/moli