Question

ce cantitate de oxid de calciu reactioneaza cu 49 g acid sulfuric cu concentratie 30%?
Multumesc !

Answer 1

x.............14,7g
CaO+H2SO4-->CaSO4+H2O
56...........98

$c = \frac{md}{ms} \times 100 \\ md = \frac{ c \times ms}{100} \\ md= \frac{30 \times 49}{100} = 14.7 \: g \: acid \: sulfuric$
MCaO=ACa+AO=40+16=56 g/mol
MH2SO4=2AH+AS+4AO
MH2SO4=2×1+32+4×16=98 g/mol
$x = \frac{56 \times 14.7}{98} = 8.4 \: g \: oxid \: de \: calciu$