Question

Ce cantitate de solutie de HCl de concentratie 36,5% poate neutraliza 2 moli Ca(OH)2 ?

Answer 1

Salut!
2....................x
Ca(OH)2+2HCl—>CaCl2+2H2O
1.....................2

x=2•2=4 moli HCl

n=m/M=>m=n•M=4•36,5=146 grame HCl
iar acum 146 este ms
c=(md/ms)•100=>md=(c•ms)/100
md=(36,5•146)/100=53,29 grame HCl