Question

Ce cantitate si ce volum de dioxid de sulf se poate obtine prin arderea a 5 kg pucioasa (sulf impur) de puritate 86%

Answer 1

Am aflat cantitatea in moli, grame si kmoli, deoarece nu se specifica, iar volumul in l, in conditii normale de temperatura si presiune

Answer 2

    

          4,3 kg      xkg
          S + O2 =SO2                                         MSO2=32 +2.16=64
         32kg        64 kg


Se calculeaza puritatea sulfului

5.86:100=4,3 kg S pur                    

x=4,3.64:32=8,6 kg SO2                                           Punctul  .  inseamna
                                                                                  inmultit iar  :  inseamna
nr. moli =n=m:M                                                         impartit
n=8,6:44=0,19 moli SO2

V=0,19.22,4=4,256 litri SO2