Question

ce compozitie procentuala are ZnBr2????

Answer 1

Răspuns:

Explicație:

Zn Br2

M= 65 + 2. 80=225------> 225 g/moli

225g ZnBr2-----------65g Zn---------160g Br

100 g ---------------------x------------------y

x= 100 .65 : 225 =28,89% Zn

y= 100 .160 : 225 =71,11% Br