Question

ce compus si in ce cantitate se obtine prin arderea a 200g pulbere de aluminiu de puritate 80%? exprimati raspunsul in grame si moli

Answer 1

Răspuns:

160g                x

4Al  + 3 O2=2 Al2O3

4*27g                2*102g

Al pur=200*80%=160g

x=160*2*102:4*27=302,2g

302,2:102=29,5 moliAl2O3