Question

ce concentratie procentuala are solutia care contine 2 moli CuSo4 dizolvati in 500 g apa

Answer 1

$n = \frac{masa}{masa \: molec} \\ masa \: \: moleculara \: cuso4 = 64 + 32 + 64 = 160 \\ masa \: molec. = 160 \: g \\ 2 = \frac{masa}{160} = > \\ masa \: = 320 \: g$

ms =md+mH2O=320 +500=820 g

$c = \frac{320 \times 100}{820} = \frac{32000}{820} = 39.02\%$