Question

ce forta elastica apare intr-un restor de k=200n /m daca alungeste delata l = 2 cm
k=200n/m
delta l =2 cm = 2ori 10 la 2
FE=

Answer 1

Răspuns:

K = 200 N/m

△l = 2 cm = 0.02 m

Fe = K • △l

$f = 200 \times \frac{2}{100} = 2 \times 2 = 4$

Fe = 4 N (Newton)