Question

ce lungime are un resort k=50 N/m daca suspendam de el un corp cu volumul V=8cm cubi si ro=7,8 kg/cm cubi stind ca lungime resortului nedeformat estd l0=5cm

Answer 1

Se da:
k=50N/m
V=8cm³
p=7,8kg/cm³
l0=5cm=0,05m
l1=?m

Formule:
[tex]Fel=kx\\ mg=k(l1-l0)\\ \frac{Vpg}{k}+l0=l1\\ [/tex]
Calcule:
$l1= \frac{8*7,8*10}{50}+0,05= 12,53m$