Question

Ce masa are amestecul de substante care contin 0,3 moli de carbonat de calciu di 0,2 moli de carbonat de magneziu?

Answer 1

1 mol CaCO3=ACa+AC+3*AO=40+12+3*16=52+48=100g
0.3 mol CaCO3=30g

1 mol MgCO3=24+12+3*16=24+12+48=84g
0.2 mol MgCO3=0.2*84=16.8

30g+16.8g =46.8g