Question

ce masa are benzina necesara pentru a umpleun rezervor care pot intra 50 kg de apa?

rezolvare completa!

 

Answer 1

Datele problemei:
$m_{1}$=50 kg (apa)
$RO_{2}$=$800 \frac{kg}{ m^{3} }$ (benzina)
$m_{2}$=? (benzina)
$RO_{1} =1000 \frac{kg}{ m^{3} }$ (apa)
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Rezolvare:
$RO_{1} = \frac{ m_{1} }{V} => V= \frac{ m_{1} }{ RO_{1} } = \frac{50kg}{1000 \frac{kg}{ m^{3} } }= 0,05 m^{3}$
$RO_{2}= \frac{ m_{2} }{V} => m_{2}= RO_{2}*V=800 \frac{kg}{ m^{3} }*0,05 m^{3}=40kg$