Question

ce masa de apa trebuie adaugata la 500 ml solutie 68% HNO3 cu p=1,4g /ml pt a obține o soluție de 10%

Answer 1

p=ms/V==>ms=p*V=1.4*500=700g

Cp=md/ms*100==>md=Cp*ms/100=68*700/100=476g HNO3

ms=md+mH2O==>mH2O=ms-md=700-476=224g

Cp=md/md+mH2O=> 10=476/700+mH2O*100==>10(700+mH2O)=47600==>7000+10mH2O=47600==>10mH2O=40600==>mH2O=4060g ? Nu sunt sigur dacă e bine