Question

Ce masa de cupru poate fi atacata la cald de 400 g de solutie 31.5% de acid azotic??

Answer 1

Cp=md/ms*100==>md=Cp*ms/100=31.5*400/100=126g HNO3

n=md/M=126/63=2 moli HNO3

Cu + 2HNO3 --->  Cu(NO3)2 + H2

1mol Cu...........2 moli HNO3
x=1mol..................2 moli HNO3

n=m/M==>m=n*M=1*64=64g Cu

MCu=64g/mol
MHNO3=63g/mol