Question

Ce masa de oxid de calciu se obtine prin descompunerea a 200g calcar de puritate 80 la suta. Cati moli de dioxid de carbon se degaja din reactie?

Answer 1

p=mpur/mimpur *100 => m pur=p*mimpur/100=80*200/100=160g CaCO3

CaCO3 = CaO + CO2

MCaCO3=ACa+AC+3AO=40+12+3*16=100g/mol

MCaO=ACa+AO=40+16=56g/mol

100g CaCO3.......................56g CaO
160g CaCO3.......................x= Calculeaza !!!

100g CaCO3.............................1mol CO2
160g CaCO3..............................x= Calculeaza !!!