Question

Ce masa de substanta corespunde in urmatoarele substanțe?
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Answer 1

Răspuns:

Explicație:

a.    5 moli Al (OH)3

M = 27 + 3.16 + 3=78------> 78g/moli

n = m : M

m = n . M

m= 5moli . 78=390 g AL (OH )3

b.     2 kmoli HCl =2000moli

MHCl=1 + 35,5=36,5 -----> 36,5g/moli

m= 2000 moli. 36,5g/moli= 73000 g= 73 kg HCl

c.  

6023.10 la 25= 60,23 . 10²³  

n= 60,23 .10²³: 6,023.10²³=10 moli H2

m=10moli.2g/moli=20g H

d.   0,1 moli HNO3

M= 1+14 + 3.16=63-------> 63g/moli

m= 0,1 moli . 63g/moli= 6,3 g HNO3