Question

Ce masa de sulfat de bariu se obtine prin reactia sulfatului de magneziu cu 52g clorura de bariu .
Sa ma ajutati va rog !!!

Answer 1

miu(M)= (137gBa+2x35,5gCl)/mol= 208g/mol BaCl2
miu(M)= ( 137gBa+32gS+4x16gO)/mol=233g/mol  BaSO4\

ecuatia reactiei:
1mol.................................1mol
BaCl2 + MgSO4---->BaSO4 + MgCl2
208g...............................233g
52g..................................m= 52x233/208 g BaSO4=  ..... CALCULEAZA! .........