Question

ce numar este cu 12,5% mai mic decit suma numerelor$6 \sqrt32si4 \sqrt72$

Answer 1

[tex]6\sqrt{32}=6*4\sqrt{2}=24\sqrt{2}\\ 4\sqrt{72}=4*6\sqrt{2}=24\sqrt2}\\ 24\sqrt2}+24\sqrt2}=48\sqrt{2}\\ 48\sqrt{2}- \frac{12,5}{100}*48\sqrt{2}=\\ 48\sqrt{2}- \frac{1}{8}*48\sqrt{2}=\\ 48\sqrt{2}-6\sqrt{2}=42\sqrt{2} [/tex]